x^2+x-4830=0

Solution for x^2+x-4830=0 equation:

x^2+x-4830=0

a = 1; b = 1; c = -4830;
Δ = b2-4ac
Δ = 12-4·1·(-4830)
Δ = 19321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19321}=139$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-139}{2*1}=\frac{-140}{2}
=-70
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+139}{2*1}=\frac{138}{2}
=69
$